Skip to content# Multiplying an Int by a Double in Swift

### Multiplying Int by Double

### Implicit Conversion

### Dealing with Potential Loss of Precision

— Swift, Programming, Numeric Operations — 1 min read

Before we dive into the specifics of multiplying an int by a double, let's take a moment to understand the numeric data types available in Swift. Swift provides several built-in numeric types, including integers (Int) and floating-point numbers (Float, Double).

**Int**: This represents whole numbers with no fractional component.**Double**: This is Swift's primary type for representing decimal numbers, providing at least 15 decimal digits of precision.

Multiplying an integer by a double involves working with two different data types. In Swift, when you multiply an integer by a double, the result is automatically promoted to a double. Let's consider an example to illustrate this:

`1let intValue = 52let doubleValue = 2.53let result = Double(intValue) * doubleValue4print(result) // Output: 12.5`

In the above example, `intValue`

is explicitly converted to a Double by using `Double(intValue)`

before the multiplication. As a result, the product of the multiplication is of type Double.

Swift also supports implicit conversion during arithmetic operations. When you use an integer with a floating-point number in an arithmetic operation, Swift will implicitly convert the integer to the appropriate floating-point type. Here's an example to demonstrate this:

`1let result = 3 * 4.02print(result) // Output: 12.0`

In this case, the integer `3`

is implicitly converted to a Double to perform the multiplication with `4.0`

, resulting in a Double value.

It's important to be mindful of potential loss of precision when working with mixed-type arithmetic operations. Although Swift promotes the result to the wider type (in this case, a Double), there may still be scenarios where precision could be lost due to the inherent nature of working with floating-point numbers. Always be cautious of such scenarios, especially in cases where high precision is required.